Program 19

                                                                          Program 19

Write a function called number_of_factors that takes an integer and returns how many factors the number has.

def number_of_factors(num):

    count=0

    for i in range(1,num+1):

        if(num%i==0):

            print(i,end=" ")

            count=count+1

    return(count)

num=int(input("Enter the integer:"))

c=number_of_factors(num)

print("\n factors the %d number has =%d"%(num,c))

output:

>>> 

======= RESTART: D:\old\r19 lab-python\19.py ===============

Enter the integer:25

1 5 25 

 factors the 25 number has =3

>>> 

=========== RESTART: D:\old\r19 lab-python\19.py ============

Enter the integer:16

1 2 4 8 16 

 factors the 16 number has =5

>>>